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If you have the volume of a cylinder 128(pi)in^3, the height of 8, and X as the diameter, what's X?

Guest Mar 20, 2017
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 #1
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128pi  = pi * radius^2 * height

 

128 pi  =  pi * radius^2 * 8       divide both sides by 8pi

 

128pi / [ 8 pi ]    = radius^2

 

128/8   =   radius^2

 

16 =  radius^2         take the square root of  both sides

 

4  = radius........so.....the diameter  = twice this =  8

 

 

cool cool cool

CPhill  Mar 20, 2017
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Thank you so much!!!

Guest Mar 20, 2017

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