If you have the volume of a cylinder 128(pi)in^3, the height of 8, and X as the diameter, what's X?

128pi = pi * radius^2 * height

128 pi = pi * radius^2 * 8 divide both sides by 8pi

128pi / [ 8 pi ] = radius^2

128/8 = radius^2

16 = radius^2 take the square root of both sides

4 = radius........so.....the diameter = twice this = 8

Thank you so much!!!