+0  
 
+1
213
2
avatar

If you have the volume of a cylinder 128(pi)in^3, the height of 8, and X as the diameter, what's X?

Guest Mar 20, 2017
 #1
avatar+87294 
+1

128pi  = pi * radius^2 * height

 

128 pi  =  pi * radius^2 * 8       divide both sides by 8pi

 

128pi / [ 8 pi ]    = radius^2

 

128/8   =   radius^2

 

16 =  radius^2         take the square root of  both sides

 

4  = radius........so.....the diameter  = twice this =  8

 

 

cool cool cool

CPhill  Mar 20, 2017
 #2
avatar
0

Thank you so much!!!

Guest Mar 20, 2017

7 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.