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A tube of tennis balls is a cylinder with a radius of 3.8cm. It contains 3 balls which fit exactly inside it. What is the Volume of the empty space in the tube?

Guest May 18, 2017
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2+0 Answers

  #2
avatar +73854 
+2

 

The height of the cylinder  = 6 times the radius of one tennis ball = 6 * 3.8 cm  = 22.8 cm

 

The volume of the cylinder  =    pi * radius^2 * height =

 

pi * (3.8)^2 * 22.8  cm^3      (1)

 

The volume of the tennis balls  [3 spheres ]  is

 

3 ( 4/3) * pi * (3.8)^3    cm^3   =    4 pi (3.8)^3  cm^3      (2)

 

The empty space is   (1)  - (2)   =

 

pi * (3.8)^2 * 22.8  - 4 pi (3.8)^3   ≈ 344.77 cm^3

 

 

cool cool cool

CPhill May 18, 2017
  #3
+1

thank you very much

i did 3.8*2 instead of 3.8^2 i guess thats why i got it wrong X)

Guest May 18, 2017
edited by Guest  May 18, 2017

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