We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A tube of tennis balls is a cylinder with a radius of 3.8cm. It contains 3 balls which fit exactly inside it. What is the Volume of the empty space in the tube?

Guest May 18, 2017

#2**+2 **

The height of the cylinder = 6 times the radius of one tennis ball = 6 * 3.8 cm = 22.8 cm

The volume of the cylinder = pi * radius^2 * height =

pi * (3.8)^2 * 22.8 cm^3 (1)

The volume of the tennis balls [3 spheres ] is

3 ( 4/3) * pi * (3.8)^3 cm^3 = 4 pi (3.8)^3 cm^3 (2)

The empty space is (1) - (2) =

pi * (3.8)^2 * 22.8 - 4 pi (3.8)^3 ≈ 344.77 cm^3

CPhill May 18, 2017