Tank X and Tank Y are each filled with some water. When water from Tank Y is poured into Tank X until it reaches the brim, there will be 16 litres of water left in Tank Y. When water from Tank X is poured into Tank Y until it reaches the brim, there will be 54 litres of water left in Tank X. The capacity of Tank X is three times the capacity of Tank Y. How many more litres of water are needed to fill both tanks to their brims?
Please don't use algebra method as I am rather new to it. Please try to use a traditional method. Hoping for your immediate reply. Thanks.
Tank X = 3(Tank Y)
Tank X = W(water) + 56(liters)
Tank Y = W(water) + 16(liters)
Therefore: W + 56 = 3(W + 16)
W + 56 = 3W + 48
-W = -W
56 = 2W + 48
-48 = -48
8 = 2W
4 = W
Tank X = 4 + 56 = 60 liters
Tank Y = 4 + 16 = 20 liters
4 liters of water is needed to fill both tanks.