I´m making beer, and I need something calculated. If i have 1.4 liter of fluid at 22 celsius, and I add 2dl of 50 celsius, what is the total temperature in the 1,6 liters?
Assuming the density and specific heat capacity stay essentially constant over the temperature range of interest you can just do
T = (1.4*22 + 0.2*50)/1.6 = 25.5°C
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