we eat 2/3 of our chocolates then the next day we eat another 2/3 and we are left with 6 how many chocolates do we have in total?

I like that answer thanks anon. :)

Another way to look at it is you start with x choc

you eat 2/3 so you are left with 1/3 THAT IS you now have    x*1/3

now you eat another 2/3 of that so you have 1/3 of it left SO YOU NOW HAVE    (x*1/3)*1/3 = x/9

but you really have 6 chocs so

 

$${\frac{{\mathtt{x}}}{{\mathtt{9}}}} = {\mathtt{6}}$$

 

$${\mathtt{x}} = {\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{6}}$$       = 54 chocs

Do the oposite operation

 

6=1/3 (what was left)

X=6*3 (total before you eat 2/3)

X=6*3=18

 

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18=1/3

Y=18*3 (total of chocolates before you eat)

Y=18*3=54//