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We have a triangle $\triangle ABC$ where $AC = 17,$ $BC = 15,$ and $AB = 8.$ Let $M$ be the midpoint of $AB.$ What is the length of $CM$?

 Aug 16, 2018
 #1
avatar+98130 
+1

Let A  = (0,8)   B  =(0,0)   C  = (15,0)  and M  = (0,4)

 

So CM  = √ [ (15 - 0) ^2  + ( 0 - 4)^2 ] =   √ [15^2 + 4^2 ]   =  √ [ 225 + 16]  = √241 ≈ 15.52 units

 

 

cool cool cool

 Aug 16, 2018

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