We know $\angle A=45^\circ, \angle B=15^\circ,$ and $BC=\sqrt{6}.$ What is AB
[asy] size(5cm); pair A,B,C; A=(0,0); B=(5,0); C=(1,1); draw(A--B--C--A); label("$A$",A,SW); label("$B$",B,SE); label("$C$",C,N); [/asy]
By the Sine Law, AB = 2 + 3*sqrt(3).