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How do you solve weighted averages where you are trying to take, let's say, 80% solution that has 20 gallons, and add it to x amount of 30% solution to make 50% solution?

 Jan 7, 2016

Best Answer 

 #1
avatar
+5

Start with 'x'

Say that is the amount of 30% solution you need to add   .3x

   then the final volume will be 20 gallons PLUS x    or 20 + x

     this new, bigger volume is to be 50%    or  .5  (20+x)

 

the two sides of the equation have to equal :  what you started with plus what you added have to equal the final solution

 

you started with   .8(20) and added .3x

so

.8(20) + .3x   has to equal   .5 (20+x)

 

.8 (20) +.3x = .5 (20+x)

16 + .3x = 10 + .5x    solve for 'x'

6 = .2x

x = 30     gallons of 30% solution  

 Jan 7, 2016
 #1
avatar
+5
Best Answer

Start with 'x'

Say that is the amount of 30% solution you need to add   .3x

   then the final volume will be 20 gallons PLUS x    or 20 + x

     this new, bigger volume is to be 50%    or  .5  (20+x)

 

the two sides of the equation have to equal :  what you started with plus what you added have to equal the final solution

 

you started with   .8(20) and added .3x

so

.8(20) + .3x   has to equal   .5 (20+x)

 

.8 (20) +.3x = .5 (20+x)

16 + .3x = 10 + .5x    solve for 'x'

6 = .2x

x = 30     gallons of 30% solution  

Guest Jan 7, 2016
 #2
avatar+128707 
+5

.80 (20) + .30x  = .50 (x + 20)

 

16 +.30x = .50x + 10

 

6 = .20x 

 

x = 30  gallons of the 30% solution

 

 

 

cool cool cool

 Jan 7, 2016

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