\(x(x+1)=272 \\ x^2 + x =272 \\ (x+1/2)^2 -\dfrac 1 4 = 272 \\ (x+1/2)^2 = \dfrac {1089}{4} \\ x+\dfrac 1 2 = \sqrt{\dfrac {1089}{4}} = \dfrac {33}{2} \\ x=\dfrac {32}{2} = 16 \\ \mbox{the two numbers are }16 \mbox{ and } 17\)
\(-16 \mbox{ and } -17 \mbox{ work as well.}\)
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