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The truncated right circular cone has a large base radius 8 cm and a small base radius of 4 cm. The height of the truncated cone is 6 cm. How many cm^3 are in the volume of this solid?

cjxie0613  Nov 29, 2018
 #1
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The truncated right circular cone has a large base radius 8 cm and a small base radius of 4 cm. The height of the truncated cone is 6 cm. How many cm^3 are in the volume of this solid?

 

This is known as a "frustum" of  a cone

 

The volume is given by

 

pi * ( height / 3 )  ( R^2  + Rr  + r^2)     

Where R  is the larger base radius and r is the smaller base radius

 

So we have

 

pi * ( 6/3) ( 8^2 + 8*4 + 4^2)     =

 

pi *  (2) ( 64 + 32 + 16) =

 

2pi * ( 112) =

 

224 pi cm^3 ≈  703.7 cm^3

 

 

cool cool cool

CPhill  Nov 29, 2018

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