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# what are 2 numbers that add to potitve 5 and times to give -7

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what are 2 numbers that add to potitve 5 and times to give -7

Oct 16, 2021

#1
+675
+1

Hello,

($$x+y=5$$) and ($$xy=-7$$),

($$x=5-y$$) and ($$xy=-7$$),

$$(5-y)y=-7$$),

so y is now:

($$y=\frac{5+\sqrt{53}}{2}$$) and ($$y=\frac{5-\sqrt{53}}{2}$$),

($$x=5-\frac{5+\sqrt{53}}{2}$$) and ($$y=\frac{5-\sqrt{53}}{2}$$),

($$x=5-\frac{5+\sqrt{53}}{2}$$) and ($$x=5-\frac{5-\sqrt{53}}{2}$$),

so x is now:

($$x = \frac{5-\sqrt{53}}{2}$$) and ($$x = 5-\frac{5-\sqrt{53}}{2}$$),

($$x = \frac{5-\sqrt{53}}{2}$$) and ($$x = \frac{5+\sqrt{53}}{2}$$),

So there are 2 possibilities, namely:

$$x,y=(\frac{5-\sqrt{53}}{2}, \frac{5+\sqrt{53}}{2})$$ and the second possibility, namely:

$$x,y=(\frac{5+\sqrt{53}​​​​​​​​}{2}, \frac{5-\sqrt{53}}{2})$$

Straight

Oct 16, 2021
#2
+675
+1

There is a hard methode to get $$\sqrt{53}$$ , I have left it out

Oct 16, 2021