what are 2 numbers that add to potitve 5 and times to give -7

Hello,

(\(x+y=5\)) and (\(xy=-7\)),

(\(x=5-y\)) and (\(xy=-7\)),

\((5-y)y=-7\)),

so y is now:

(\(y=\frac{5+\sqrt{53}}{2}\)) and (\(y=\frac{5-\sqrt{53}}{2}\)),

(\(x=5-\frac{5+\sqrt{53}}{2}\)) and (\(y=\frac{5-\sqrt{53}}{2}\)),

(\(x=5-\frac{5+\sqrt{53}}{2}\)) and (\(x=5-\frac{5-\sqrt{53}}{2}\)),

so x is now:

(\(x = \frac{5-\sqrt{53}}{2}\)) and (\(x = 5-\frac{5-\sqrt{53}}{2}\)),

(\(x = \frac{5-\sqrt{53}}{2}\)) and (\(x = \frac{5+\sqrt{53}}{2}\)),

So there are 2 possibilities, namely:

\(x,y=(\frac{5-\sqrt{53}}{2}, \frac{5+\sqrt{53}}{2})\) and the second possibility, namely:

\(x,y=(\frac{5+\sqrt{53}​​​​​​​​}{2}, \frac{5-\sqrt{53}}{2})\) 

Straight

There is a hard methode to get \(\sqrt{53}\) , I have left it out