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What are the coordinates of the hole in the graph of the function f(x) ?

Hev123  Apr 12, 2018
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f(x)=x^2-9/x-3

f(x)=(x+3)(x-3)/(x-3)

x-3=0

x=3

3^2-9/3-3

9-9/3-3

0/0=0

y=0

hole at (3, 0)

 

 

winkwinkwink

lynx7  Apr 12, 2018

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