Hi, I need help with this one question:
What are the coordinates of the hole in the graph of the function f(x)?
f(x) = x^2+4x-12 / x-2
f(x) = (x^2+4x-12) / ( x-2 )
This will be undefined (have a hole ) for the x value that gives the form 0/0
Factor the numerator
[(x + 6) (x - 2) ] / (x - 2)
Nothe that when = 2, we will have the form 0/0
So.....to find the y coordinate of the hole, cancel the ( x - 2) factors and sub 2 into x + 6
So.....the coordinate of the "hole" is (2 , 2 + 6) = (2,8)