Hi, I need help with this one question:

What are the coordinates of the hole in the graph of the function f(x)?

f(x) = x^2+4x-12 / x-2

Guest Apr 18, 2018

#1**+1 **

f(x) = (x^2+4x-12) / ( x-2 )

This will be undefined (have a hole ) for the x value that gives the form 0/0

Factor the numerator

[(x + 6) (x - 2) ] / (x - 2)

Nothe that when = 2, we will have the form 0/0

So.....to find the y coordinate of the hole, cancel the ( x - 2) factors and sub 2 into x + 6

So.....the coordinate of the "hole" is (2 , 2 + 6) = (2,8)

CPhill Apr 18, 2018