+0  
 
0
102
1
avatar

Hi, I need help with this one question:

 

What are the coordinates of the hole in the graph of the function f(x)?

 

f(x) = x^2+4x-12 / x-2

Guest Apr 18, 2018
 #1
avatar+88871 
+1

f(x) =  (x^2+4x-12) / ( x-2 )

 

This will be undefined (have a hole )  for the x value  that gives the form  0/0

 

Factor the numerator

 

[(x + 6) (x - 2) ] / (x - 2)

 

Nothe that when  = 2, we will have the form  0/0

 

So.....to find the y coordinate of the hole,  cancel the ( x - 2) factors and sub  2  into  x + 6

 

So.....the coordinate of the  "hole"  is    (2 , 2 + 6)  =  (2,8)

 

 

cool cool cool

CPhill  Apr 18, 2018

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