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Solved it nevermind thanks :D

WhichWitchIsWhich  Nov 13, 2017
edited by WhichWitchIsWhich  Nov 13, 2017
 #1
avatar+92620 
+1

x^3-x^2+x+1 =x^3+x^2+x-1 

 

Subtract x^3, x   from each side

 

-x^2 + x + 1  =  x^2 - 1

 

-x^2 + 1  = x^2 - 1    rearange as

 

0  =  2x^2 - 2

 

2x^2 - 2  = 0     divide through by 2

 

x^2 - 1  = 0    factor

y = (1)^3 + (1)^2 + 1 - 1  =

(x + 1) ( x - 1)  = 0 

 

Set each factor to 0 and solve for x

 

And  x = 1   or x = -1

 

And using  x^3+x^2+x-1   

 

y = (1)^3 + (1)^2 + 1 - 1  =  2

 

y = (-1)^3 + (-1)^2 - 1 - 1  =  -2

 

So the solutions are  (1, 2)  and (-1. -2)

 

 

cool cool cool  

CPhill  Nov 13, 2017

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