Eh.....you're not "stupid".....you just need a little help.....!!!
Here we go....
Putting "1" into g(x), we have
(1)^3 + (1)^2 + (1) - 1 = 1 + 1 + 1 - 1 = 2
Putting "-1" into g(x) we have
(-1)^3 + (-1)^2 + (-1) - 1 = -1 + 1 - 1 - 1 = -2
So...the points of intersection are (1, 2) and (-1, -2)
Not too bad, huh???
x3 - x2 + x +1 = x3 + x2 +x -1
- x2 + 1 = x2 -1
x2 = 1
x = ±1
You can take it from here
.
Insert the values of x into either f(x) or g(x) and work out the values.
The points will be (1, f(1)); (-1, f(-1))
.
Eh.....you're not "stupid".....you just need a little help.....!!!
Here we go....
Putting "1" into g(x), we have
(1)^3 + (1)^2 + (1) - 1 = 1 + 1 + 1 - 1 = 2
Putting "-1" into g(x) we have
(-1)^3 + (-1)^2 + (-1) - 1 = -1 + 1 - 1 - 1 = -2
So...the points of intersection are (1, 2) and (-1, -2)
Not too bad, huh???