+0

What are the coordinates?

0
99
2

What are the coordinates of the vertex of the parabola?

y=3/4x^2−6x+15

May 22, 2019
edited by Guest  May 22, 2019

#1
+1606
+1

Hint: Use formula $$\frac{-b}{2a}$$.

This is used to find the vertex, it should be trivial

May 22, 2019
#2
+103982
+2

y = (3/4)x^2 - 6x + 15

We have the form y  = Ax^2 + Bx + C

The x coordinate of the vertex is given by   -B/[2A] =  - -6 / [ 2(3/4)] = 6 / [ 6/4] = 6 *4/6  = 4

So....the y coordinate of the vertex is g(3/4)(4)^2 - 6(4) + 15  =   (3/4)16 - 24 + 15 =  12 - 24 + 15  = 3

So....the vertex is  ( 4, 3)

Here's a graph : https://www.desmos.com/calculator/vkss4gjgpf

May 22, 2019