Last one (c)
Max A(0,3)
Min (2pi,-3)
Period = 2(2pi-0)=4pi
Amplitude = 0.5(3--3) = 3 =a
midline y=0
y=sinx passes through (0,0) so there is a phase shift here of -pi
y=asin[b(x-c)]
\(\frac{2\pi}{b}=4\pi\\ b=0.5\)
\(y=3sin[0.5(x--pi)]\\ y=3sin[0.5(x+\pi)]\)
