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A) p(r)=2r2+2r1

B) h(t)=4.9(t+3)2+45.8

 Jul 12, 2015

Best Answer 

 #1
avatar+23246 
+5

A)  p(r)  =  2r2 + 2r - 1

To make it easier to write, I am going to replace p(r) with y:

         y  =  2r2 + 2r - 1

Now, solve for r:

     y + 1  =  2r2 + 2r

     y + 1  =  2(r2 + r)

Complete the square:

    y + 1 + ½  =  2(r2 + r + ¼)

    y + 3/2  =  2(r2 + r + ¼) 

   (y + 3/2)/2  =  (r + ½)2 

Take the square root (using the positive portion):

  √( y/2 + 3/4 )  =  r + ½

  r  =  -½ +√( y/2 + 3/4 )

  r  =  -½ +√( p(r)/2 + 3/4 )

 

B)  h(t)  =  - 4.9(t + 3)2 + 45.8

         y  =  - 4.9(t + 3)2 + 45.8

    y - 45.8  =  - 4.9(t + 3)2 

  (y - 45.8) / -4.9  =   (t + 3)2 

  √( (y - 45.8) / -4.9 )  =  t + 3

  t  =  -3 +  √( (y - 45.8) / -4.9 )

  t  =   -3 +  √( (h(t) - 45.8) / -4.9 )

 Jul 12, 2015
 #1
avatar+23246 
+5
Best Answer

A)  p(r)  =  2r2 + 2r - 1

To make it easier to write, I am going to replace p(r) with y:

         y  =  2r2 + 2r - 1

Now, solve for r:

     y + 1  =  2r2 + 2r

     y + 1  =  2(r2 + r)

Complete the square:

    y + 1 + ½  =  2(r2 + r + ¼)

    y + 3/2  =  2(r2 + r + ¼) 

   (y + 3/2)/2  =  (r + ½)2 

Take the square root (using the positive portion):

  √( y/2 + 3/4 )  =  r + ½

  r  =  -½ +√( y/2 + 3/4 )

  r  =  -½ +√( p(r)/2 + 3/4 )

 

B)  h(t)  =  - 4.9(t + 3)2 + 45.8

         y  =  - 4.9(t + 3)2 + 45.8

    y - 45.8  =  - 4.9(t + 3)2 

  (y - 45.8) / -4.9  =   (t + 3)2 

  √( (y - 45.8) / -4.9 )  =  t + 3

  t  =  -3 +  √( (y - 45.8) / -4.9 )

  t  =   -3 +  √( (h(t) - 45.8) / -4.9 )

geno3141 Jul 12, 2015
 #2
avatar+118608 
0

Thanks Geno :)

 Jul 12, 2015

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