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avatar+303 

a. (4,5π/ 3)

 

b. (2,11π/ 6)

 

c. (2,5π/ 3)

 

d. (4,11π/ 6)

 Feb 8, 2021
 #1
avatar+116125 
+2

Rectangular  coordinates =  ( r*cos ( theta) , r * sin  (theta))

 

a)   ( 4 cos 5pi/3, 4sin5pi/3)  =  ( 4cos300°, 4sin 300°) =  4 (1/2) , 4 (-sqrt (3)/2) )  = ( 2, - 2 sqrt (3) )

 

b)  (2, 11pi/6)  =  ( 2 cos 330 , 2 sin 330)  =  ( 2sqrt (3) /2  ,  2 (-1/2) ) =  (sqrt (3) ,- 1)

 

You should be able to  finish the last two.....let me  know if you get  stuck

 

 

cool cool cool

 Feb 8, 2021
 #2
avatar
+1

Find    'r' via pythag theorem

2^2 + (-2 sqrt3)^2 = r^2

r =            so answer A or B are possibles

   find angle   arctan (-2sqrt3 /2)  = -60 degrees   or  5pi/3           Do you see how to do it?

 Feb 8, 2021

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