If f(x) = a+bx, what are the real values of a and b such that f(f(f(1))) = 29 and f(f(f(0))) = 27

thess Oct 16, 2018

#1**+1 **

f(f(f(x)))=a+b( a+b( a+bx))

f(f(f(0)))=a+b(a+b(a))=27

f(f(f(1)))=a+b(a+b(a+b))=29

f(f(f(0)))=a+ba+b^2a=27

f(f(f(1)))=a+ba+ab^2+b^3=29

(1) a+ba+b^2a=27 -> f(f(f(1)))=(1)+b^3=29 so 27 + b^3 = 29 <=> b^3 = 29-27 <=> b^3 = 2 <=> b = \(\sqrt[3]{2}\)\(\)

after in f(f(f(1))) you are replacing and find the a!

Dimitristhym Oct 16, 2018