What are the rectangular coordinates of the polar coordinates (3√2,−π/6)
Give the values rounded to the nearest hundredth.
x = r cosθ = 3√2 cos ( -pi/6) = 3√2 ( √3/2) = 3√6/2 ≈ 3.67
y = r sin θ = 3√2 sin (-pi/6) = 3√2 (-1/2) = -3/√2 ≈ -2.12
