What are the roots of the equation?


SamJones  Jan 27, 2018

New Year, New Start, New Answer!

First answer of the year for me.


Alright, I'll try to explain this the best I can using a keyboard. laugh


The equation is x^2(6x - 11)(7x - 8) = 0

So, you have to figure out what you can put in for x for the whole thing to equal 0.

Roots mean possible solutions.


Let's "divide" the equation into 3 parts. 


We know that anything multiplied by 0 is 0.

And 0 to the power of anything is still 0. 

So if you plug in 0 for x^2(6x - 11)(7x - 8) = 0, You get 0 (it would look like "0(6x-11)(7x-8)" )

So the first root is 0.


Next, let's look at the (6x - 11) part. 

Remember that anything multiplied by 0 is 0. 

So, 6x - 11 must equal to 0.




So another root is 11/6.


Finally, let's look at (7x-8) 

That should also equal 0, no matter what it is multiplied by.




The last root is 8/7


So the three roots are 0, 11/6, and 8/7.

Gh0sty15  Jan 27, 2018

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