+0  
 
0
190
1
avatar+35 

What are the solutions of the equation  2sin(4x)=1 on the interval [0,π)?

 Apr 9, 2020
 #1
avatar+111329 
+2

2sin (4x)  =  1                 divide both sides  by 2

 

sin (4x)  =  1/2

 

Note  that  sin  (x)  = 1/2  at     pi/6, 5pi/6, 13pi/6, 17pi/6

 

Dividing  these angles  by 4    gives  us  the solutions

 

x  =  pi/24 , 5pi/24, 13 pi/24 , 17 pi /24 

 

 

cool cool cool   

 Apr 9, 2020

8 Online Users