What are the solutions of the equation secxcotx=−2 on the interval [0,2π)
sec x cot x = -2
(1/cosx) (cos x/ sin x) = -2
(1/sin x ) = - 2 which also implies that
sin x = -1/2
And this is true when x = 7pi/ 6 and 11pi/6
+32 
