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What are the solutions of the equation sinxcotx=−2√2 on the interval [0,2π)?

 May 17, 2021
 #1
avatar+1821 
+1

sine(x)*cot(x)

sine(x)*cos(x)/sine(x)

cos(x) = -2sqrt(2). 

However, cos(x) must be in the range -1 to 1. 

I think there aren't any answers. 

 

=^._.^=

 May 17, 2021
 #2
avatar+119906 
0

catmg is correct .....see   the graph here :  https://www.desmos.com/calculator/yyanrxdkr3

 

 

cool cool cool

 May 17, 2021

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