what are the solutions to the equation 2x^2-x+1=0

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1383

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Guest Feb 7, 2015

+130511

+5

Best Answer

2x^2-x+1=0

This has no "real" solutions since b^2 - 4ac = (-1)^2 - 4(2)(1) = 1 - 8 = -7

CPhill Feb 7, 2015

CPhill · Answer 1 · 2015-02-07T05:33:34

2x^2-x+1=0

This has no "real" solutions since b^2 - 4ac = (-1)^2 - 4(2)(1) = 1 - 8 = -7

Melody · Answer 2 · 2015-02-07T03:09:26

Just use the quadratic formula