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What are the solutions to the equation?

SamJones  Jan 17, 2018
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 #1
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4x^3  =  405x        divide both sides by 5

 

x^3  =  81x           subtract 81x  from both sides

 

x^3  -  81x  =  0        factor

 

x ( x^2  - 81)  =  0

 

x  (x - 9) (x + 9)  =  0     and we can write  this as

 

(x - 0 )  ( x - 9)  ( x + 9 )  =  0

 

The solutions  are

 

0,  9, -9

 

 

cool cool cool

CPhill  Jan 17, 2018

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