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# What are the solutions to the system of equations?

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Pleassssse helppp me ASAP! I can only do this today,thank you

Jan 8, 2020

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Here is a hint:

\(y=x^2-5x-6\) (1)

\(y=0x^2+2x-6\) (2)

Can you substitute (2) into (1)?

Another hint, factor.

Solution:

\(2x-6=x^2-5x-6\)

\(2x=x^2-5x\)

Subtract 2x

\(x^2-7x=0\)

Factor x

\(x(x-7)=0\)

x=0 or 7

Now substitute in both equation (1) and (2) to find y

\(y=x^2-5x-6=(7)^2-5(7)-6\) (1) equation

\(y=8\)

\(y=2x-6=2(0)-6\) (2) equation

y=-6

so the answer is first choice:

(7,8) & (0,-6)

Jan 8, 2020

#1
0

Here is a hint:

\(y=x^2-5x-6\) (1)

\(y=0x^2+2x-6\) (2)

Can you substitute (2) into (1)?

Another hint, factor.

Solution:

\(2x-6=x^2-5x-6\)

\(2x=x^2-5x\)

Subtract 2x

\(x^2-7x=0\)

Factor x

\(x(x-7)=0\)

x=0 or 7

Now substitute in both equation (1) and (2) to find y

\(y=x^2-5x-6=(7)^2-5(7)-6\) (1) equation

\(y=8\)

\(y=2x-6=2(0)-6\) (2) equation

y=-6

so the answer is first choice:

(7,8) & (0,-6)

Guest Jan 8, 2020