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What are the zeros of x squared minus 2x plus 15

 Apr 15, 2015

Best Answer 

 #1
avatar+33661 
+5

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{14}}}}{\mathtt{\,\times\,}}{i}\\
{\mathtt{x}} = {\sqrt{{\mathtt{14}}}}{\mathtt{\,\times\,}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{3.741\: \!657\: \!386\: \!773\: \!941\: \!4}}{i}\\
{\mathtt{x}} = {\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3.741\: \!657\: \!386\: \!773\: \!941\: \!4}}{i}\\
\end{array} \right\}$$

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.
 Apr 16, 2015
 #1
avatar+33661 
+5
Best Answer

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{14}}}}{\mathtt{\,\times\,}}{i}\\
{\mathtt{x}} = {\sqrt{{\mathtt{14}}}}{\mathtt{\,\times\,}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{3.741\: \!657\: \!386\: \!773\: \!941\: \!4}}{i}\\
{\mathtt{x}} = {\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3.741\: \!657\: \!386\: \!773\: \!941\: \!4}}{i}\\
\end{array} \right\}$$

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Alan Apr 16, 2015

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