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What constant will make y^2 + 28y + 16 + k the square of a binomial?

 Nov 21, 2020
 #1
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y2 + 28y + 16 + k   will be the square of a binomial when:

 

16 + k  =  (1/2 * 28)2

 

16 + k  =  (14)2

 

16 + k  =  196

 

k  =  180

 

 

Check:

 

y2 + 28y + 16 + 180   =   y2 + 28y + 196   =   (y - 14)(y - 14)   =   (y - 14)2

 Nov 21, 2020

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