what do i need to do if there's a problem like this:the greatest number is twice as large as the least number, and the middle number is three more than the least number, and the sum is 75?
The greatest number is twice as large as the least number, and the middle number is three more than the least number, and the sum is 75?
Let the the least number = x
The greatest number = 2x
The middle number = x + 3
And we have
x + [x + 3 ] + 2x = 75 simplify
4x + 3 = 75 subtract 3 from both sides
4x = 72 divide both sides by 4
x = 18 this is the least
2x = 2(18) = 36 this is the greatest
x + 3 = 18 + 3 = 21 this is the middle