it equal 2
Thanks for the answer, would you please share how you got 2?Thank you
$$\\\frac{2^3*2^0}{2}-8*2^{-2}\\\\ =\frac{8*1}{2}-8*\frac{1}{2^{+2}}\\\\ =\frac{4*1}{1}-8*\frac{1}{4}\\\\ =4-2*\frac{1}{1}\\\\ =4-2\\\\ =2$$
