It depends:
$${\frac{{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{7}}}}\right)}{{\mathtt{2}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{7}}}}$$
$${\mathtt{\,-\,}}{\frac{{\mathtt{2}}}{\left({\frac{{\mathtt{7}}}{{\mathtt{2}}}}\right)}} = {\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$
See where the parenthesis makes a diference?
It depends:
$${\frac{{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{7}}}}\right)}{{\mathtt{2}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{7}}}}$$
$${\mathtt{\,-\,}}{\frac{{\mathtt{2}}}{\left({\frac{{\mathtt{7}}}{{\mathtt{2}}}}\right)}} = {\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$
See where the parenthesis makes a diference?
