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What is (2+y)³ |written out? Line AB has the equation 3x - 4y + 5 = 0. Point (p, p+2) lies on line AB. What is the value of p? |What is the gradient of line AB from the previous question?| Express √48 in the form n√3, where n is an integer.|A geometric series has first term 80 and common ratio 1/2. What are the next two terms?|

 Mar 11, 2015

Best Answer 

 #1
avatar+130516 
+5

(2 + y) ^3    = y^3 + 6y^2 + 12y + 8

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3(p) - 4(p + 2) + 5  = 0

3p - 4p - 8 + 5 = 0 

-p = 3

p = -3

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3x + 5 = 4y     divide by 4 on both sides

y = (3/4)x + 5/4  ..... using y = mx+ b ....   the slope (gradient)  = m =  3/4

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√48 = √[16 * 3 ] =  4√3

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80, 40, 20

 

  

 Mar 11, 2015
 #1
avatar+130516 
+5
Best Answer

(2 + y) ^3    = y^3 + 6y^2 + 12y + 8

-------------------------------------------------------------------------------------------------

3(p) - 4(p + 2) + 5  = 0

3p - 4p - 8 + 5 = 0 

-p = 3

p = -3

---------------------------------------------------------------------------------------------------

3x + 5 = 4y     divide by 4 on both sides

y = (3/4)x + 5/4  ..... using y = mx+ b ....   the slope (gradient)  = m =  3/4

---------------------------------------------------------------------------------------------------

√48 = √[16 * 3 ] =  4√3

---------------------------------------------------------------------------------------------------

80, 40, 20

 

  

CPhill Mar 11, 2015

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