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what is (-2x^4-3x+5x^2-x)*(x-3)

 Jan 22, 2015

Best Answer 

 #1
avatar+118724 
+5

$$\\(-2x^4-3x+5x^2-x)*(x-3)\\\\
=(x-3)(-2x^4-3x+5x^2-x)\\\\
$First simplify inside the brackets if you can$\\\\
=(x-3)(-2x^4+5x^2-x-3x)\\\\
=(x-3)(-2x^4+5x^2-4x)\\\\
=x(-2x^4+5x^2-4x)-3(-2x^4+5x^2-4x)\\\\
$now expand the brackets but be careful with the -3$\\\\
=x(-2x^4+5x^2-4x)+(-3)(-2x^4+5x^2-4x)\\\\$$

 

That is a good start - you see if you can finish it    

 Jan 23, 2015
 #1
avatar+118724 
+5
Best Answer

$$\\(-2x^4-3x+5x^2-x)*(x-3)\\\\
=(x-3)(-2x^4-3x+5x^2-x)\\\\
$First simplify inside the brackets if you can$\\\\
=(x-3)(-2x^4+5x^2-x-3x)\\\\
=(x-3)(-2x^4+5x^2-4x)\\\\
=x(-2x^4+5x^2-4x)-3(-2x^4+5x^2-4x)\\\\
$now expand the brackets but be careful with the -3$\\\\
=x(-2x^4+5x^2-4x)+(-3)(-2x^4+5x^2-4x)\\\\$$

 

That is a good start - you see if you can finish it    

Melody Jan 23, 2015

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