+2972 Ok this problem requires serious thinking
covernt all mixed number fractions into improper fractions
so, this is how anon words this situation:
4 4/9 / 1 1/5
We need to make the two fractions improper. Lets start with 4 4/9
9*4=36+4=40=40/9
1*5=5+1=6=6/5
this is division though, so now we do the recipicult, as some really picky math masters say, but if you dont care about all the math vocab, you can just say, flip the numbers 6 and 5 in reverse, so now its 5/6
get rid of division, and replace it with multiplication
making the new equation:
$$40/9 * 5/6$$
as you can see you can cross cancel 40 and 6, divide by 2
40/2=20
6/2=3
now its $$20/9 * 5/3$$
20*5=100
9*3=27
now the improper fraction is:
$${\frac{{\mathtt{100}}}{{\mathtt{27}}}}$$
Now divide 100 by 27 and lets see what we get
you see, 27 can go into 100 3 times
do this equation to figure out the remaining:
$${\mathtt{100}}{\mathtt{\,-\,}}\left({\mathtt{27}}{\mathtt{\,\times\,}}{\mathtt{3}}\right) = {\mathtt{19}}$$
Correct answer:
3 19/27 or 100/27
+2972 Ok this problem requires serious thinking
covernt all mixed number fractions into improper fractions
so, this is how anon words this situation:
4 4/9 / 1 1/5
We need to make the two fractions improper. Lets start with 4 4/9
9*4=36+4=40=40/9
1*5=5+1=6=6/5
this is division though, so now we do the recipicult, as some really picky math masters say, but if you dont care about all the math vocab, you can just say, flip the numbers 6 and 5 in reverse, so now its 5/6
get rid of division, and replace it with multiplication
making the new equation:
$$40/9 * 5/6$$
as you can see you can cross cancel 40 and 6, divide by 2
40/2=20
6/2=3
now its $$20/9 * 5/3$$
20*5=100
9*3=27
now the improper fraction is:
$${\frac{{\mathtt{100}}}{{\mathtt{27}}}}$$
Now divide 100 by 27 and lets see what we get
you see, 27 can go into 100 3 times
do this equation to figure out the remaining:
$${\mathtt{100}}{\mathtt{\,-\,}}\left({\mathtt{27}}{\mathtt{\,\times\,}}{\mathtt{3}}\right) = {\mathtt{19}}$$
Correct answer:
3 19/27 or 100/27
