what is √8x/ 3 √16x ​2

anyone PLZ HELP ME

I'm assuming no one's helped you yet because the question is too confusing.

A) Is it \(\sqrt[3]{8x} \cdot \sqrt{16x^2}\)

B) Or is it \(\sqrt{8x} \cdot \sqrt{16x^2}\)

C) Or is it \(\sqrt[3]{8x} \cdot \sqrt[3]{16x^2}\)

D) Or is it ​\(\sqrt{8x} \cdot \sqrt[3]{16x^2}\)

E) Or is it neither?

A = \(\sqrt[3]{8} \cdot \sqrt[3]{x} \cdot \sqrt{16} \cdot \sqrt{x} = 2\sqrt[3]{x} \cdot 4x = \boxed{8x\sqrt[3]{x}}\)

B = \(\sqrt{4} \cdot \sqrt{2x} \cdot \sqrt{16} \cdot \sqrt{x^2} = \boxed{8x\sqrt{2x}}\)

C = ​​\(\sqrt[3]{8} \cdot \sqrt[3]{x} \cdot \sqrt[3]{8} \cdot \sqrt[3]{2x^2} = \boxed{4x\sqrt[3]{3}}\)

D = \(\boxed{4\sqrt{2x} \cdot \sqrt[3]{2x^2}}\) 

E = Well, I can't help you there, but next time make your question clearer

I think we have

[(√8) x ] / [(³√16 ) x² ] =

[ √8 / ³√16 ] *  [   x  / x²  ]  =

 [ 2√2 / 2 ³√2 ] *  [  1/x ] =

[√2 /  ³√2 ]  * [ 1 / x ]  =

2^(1/2  − 1/3) / x  =

2^ (1/6)  / x   =

⁶√2 / x