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What is a and b in this problem:

5m+3n=14

2m+n=6

 Feb 29, 2016

Best Answer 

 #1
avatar+128564 
+10

5m+3n=14     (1)

2m+n=6  →    n  = 6 - 2m    (2)

 

Putting   (2)  into (1), we have

 

5m + 3 [ 6 - 2m ]   = 14     simplify

 

5m + 18 - 6m  =  14

 

-1m + 18 = 14       subtract 18 from both sides

 

-1m  = - 4          divide both sides by -1

 

m = 4

 

And

 

n = 6 - 2(4)   =    6  - 8   =  -2

 

So  (m, n)  = ( 4 , -2)

 

cool cool cool    

 Feb 29, 2016
 #1
avatar+128564 
+10
Best Answer

5m+3n=14     (1)

2m+n=6  →    n  = 6 - 2m    (2)

 

Putting   (2)  into (1), we have

 

5m + 3 [ 6 - 2m ]   = 14     simplify

 

5m + 18 - 6m  =  14

 

-1m + 18 = 14       subtract 18 from both sides

 

-1m  = - 4          divide both sides by -1

 

m = 4

 

And

 

n = 6 - 2(4)   =    6  - 8   =  -2

 

So  (m, n)  = ( 4 , -2)

 

cool cool cool    

CPhill Feb 29, 2016
 #2
avatar+64 
0

I am glad to have you!

Enquired  Feb 29, 2016
 #3
avatar+2972 
-3

Oh yeah here's a question you had earlier

 

 

WARNING: INCOMING FLASHBACK:

 

 

Usually I'm talking, but I'm gonna help you here

 

x+2y=8

 

x+2y=4

 

well I'm telling you, the answer is NO SOLUTION, or in simpler terms, the equations are not true

 

in order to understand, use the elimination method of solving for X & y

 

x+2y=8

-1 (X+2y=4) <----distribute here by multiplying this whole equation by -1, or make the positives negative in simpler terms

 

Now it it should look like this

 

x+2y=8

-x-2y=-4

 

now eliminate by subtraction

 

x-x=0

 

2y-2y=0

 

8-4=4

 

0=4

 

wait a minute,that is NOT true, 0 IS NOT EQUAL to 4, and there's no variable left cuz all the ones have been eliminated, therefore, there is NOT A SINGLE SOLUTION, you can't solve for x or y 

 

 

FLASHBACK ENDS HERE

 

 

youre welcome

 Mar 1, 2016
 #4
avatar+128564 
0

TR.....I think you mis-copied the problem....it was

 

x + 2y   = 8

x -  2y   = 4

 

And there definitely is a solution for this....!!!

 

 

 

cool cool cool

 Mar 1, 2016
 #5
avatar+906 
0

I'm sorry to step you down and make TR right, but he is right according to proof

 

 Mar 3, 2016
 #6
avatar+118608 
0

Hi Chris, TR and Heather,

I am totally lost on what you are saying TR and Heather.

What has some old post that has not even been address referenced got to do with the question here?

 

I guess Chris seems to have some idea that you are talking about but I don't.   indecision

Maybe I should be on the forum more often then I might 'get' what is going on.   LOL 

 Mar 3, 2016
 #8
avatar+906 
0

Yeah, just go to comment #56 of that drama post, that's where the math comes in

 

http://web2.0calc.com/questions/happy-afternoon-or-night#r56

HeatherF  Mar 3, 2016
 #7
avatar+118608 
0

By the way Chris you got it wrong.

 

The values of a and b are not known !!     ROF LOL

 Mar 3, 2016

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