what is a thirteen over five times b two over 2 divided by a negative seven over ten times b negative one over three?
(13/5) x (2b/2) / (-7/10) x (-b/3) =
(13/5) x b / (-7/10) x (-b/3) =
(13b/5) x (-10/7) x (-b/3) =
(-130b/35) x (-b/3) =
(130b^2 / 105) =
(26/21)b^2
