what is an equation of the line (-1,3),(2,-.5)?

Thank you guys soo much you helped me out a ton! thatl bring it right on up to an A!!

Using (x1, y1) = (-1, 3) and (x2, y2) = (2, -.5), find the slope of the line:

slope  =  m  =  (y2 - y1) / (x2 - x1)

Then use the slope-intercept form of a line to get the equation:  y - y1  =  m(x - x1)

Replace x1, y1, and m in the equation; simplify what you get so you have an equation with y alone on one side and an x-term and another number on the other side.

$${\frac{\left({\mathtt{y2}}{\mathtt{\,-\,}}{\mathtt{y1}}\right)}{\left({\mathtt{x2}}{\mathtt{\,-\,}}{\mathtt{x1}}\right)}}$$this is slope formula.y2 is -.5. y1 is 3. x2 is 2. x1 is-1.

-.5-3=-3.5

2-(-1)=3

slope is 3.5/3 y=3.5/3x+b 3=3.5/3(-1)+b

3=~-1.1666666666666667+b

~4.1666666666666667=b

y=3.5/3+4.1666666666666667