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avatar+238 

sqrt3(1+sqrt(2))*sqrt6(3-2*sqrt(2

 Aug 25, 2015

Best Answer 

 #1
avatar+118667 
+10

$$\\\sqrt3(1+\sqrt{2})*\sqrt{6}(3-2*\sqrt{2})\\\\
=\sqrt{3*6}*[(1+\sqrt{2})(3-2\sqrt{2})]\\\\
=\sqrt{2*9}*[1(3-2\sqrt{2})+\sqrt{2}(3-2\sqrt{2})]\\\\
=3\sqrt{2}*[3-2\sqrt{2}+3\sqrt{2}-2\sqrt{2}\sqrt{2}]\\\\
=3\sqrt{2}*[3+\sqrt{2}-2*2]\\\\
=3\sqrt{2}*[\sqrt{2}-1]\\\\
=6-3\sqrt{2}$$

 

You need to check this answer :)

 Aug 25, 2015
 #1
avatar+118667 
+10
Best Answer

$$\\\sqrt3(1+\sqrt{2})*\sqrt{6}(3-2*\sqrt{2})\\\\
=\sqrt{3*6}*[(1+\sqrt{2})(3-2\sqrt{2})]\\\\
=\sqrt{2*9}*[1(3-2\sqrt{2})+\sqrt{2}(3-2\sqrt{2})]\\\\
=3\sqrt{2}*[3-2\sqrt{2}+3\sqrt{2}-2\sqrt{2}\sqrt{2}]\\\\
=3\sqrt{2}*[3+\sqrt{2}-2*2]\\\\
=3\sqrt{2}*[\sqrt{2}-1]\\\\
=6-3\sqrt{2}$$

 

You need to check this answer :)

Melody Aug 25, 2015
 #2
avatar+129849 
+5

I assume this is:

sqrt3(1+sqrt(2))*sqrt6(3-2*sqrt(2))   ....so we have

 

√3(1 + √2 ) ( √6)(3 - 2√2)  =

 

√18( 1 + √2 ) ( 3 - 2√2 ) =

 

√18 ( 3 + 3√2 - 2√2 - 4) =

 

√18( √2 - 1) =

 

√36  - √18 =

 

6 - 3√2

 

 

 Aug 25, 2015
 #3
avatar+129849 
0

It's correct, Melody.....

 

 

 Aug 25, 2015
 #4
avatar+118667 
0

Thanks Chris :)

 Aug 25, 2015

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