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What is I?

 Jun 23, 2015

Best Answer 

 #2
avatar+427 
+5

To expand on what anonymous said: the imaginary number is the square root of -1, this is because there is no possible "real" answer to it, but you can use the imaginary number to calculate things (often used in engineering).

$${i} = {\sqrt{-{\mathtt{1}}}}$$

Sometimes you might come across something with a negative surd. To show this in terms of "i", just seperate the square root of -1 from the rest of the surd.

Example:

Let's so I want 7*square-root(-16 * 9):

$${\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{\left(-{\mathtt{16}}\right){\mathtt{\,\times\,}}{\mathtt{9}}}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{-{\mathtt{25}}}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{25}}}}{\mathtt{\,\times\,}}{\sqrt{-{\mathtt{1}}}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{i}$$

$${\mathtt{35}}{i}$$

 Jun 23, 2015
 #1
avatar
+5

the i stands for imaganery number. for examply, 2i= 2 imaganery number.

 Jun 23, 2015
 #2
avatar+427 
+5
Best Answer

To expand on what anonymous said: the imaginary number is the square root of -1, this is because there is no possible "real" answer to it, but you can use the imaginary number to calculate things (often used in engineering).

$${i} = {\sqrt{-{\mathtt{1}}}}$$

Sometimes you might come across something with a negative surd. To show this in terms of "i", just seperate the square root of -1 from the rest of the surd.

Example:

Let's so I want 7*square-root(-16 * 9):

$${\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{\left(-{\mathtt{16}}\right){\mathtt{\,\times\,}}{\mathtt{9}}}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{-{\mathtt{25}}}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{25}}}}{\mathtt{\,\times\,}}{\sqrt{-{\mathtt{1}}}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{i}$$

$${\mathtt{35}}{i}$$

Sir-Emo-Chappington Jun 23, 2015

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