What is negative 3 over positive 15 times the absolute value of negative 15? Please help me!!
-3/15 x l-15l
Simplify the following: (-3 abs(-15) x)/15
The gcd of -3 and 15 is 3, so (-3 x abs(-15))/15 = ((3 (-1)) x abs(-15))/(3×5) = 3/3×-(x abs(-15))/5 = -(x abs(-15))/5: (-1 abs(-15) x)/5
Since -15<=0, then abs(-15) = 15: -(15 x)/5
15/5 = (5×3)/5 = 3: Answer: |-3 x
Simplify the following: (-3 abs(-15))/15
The gcd of -3 and 15 is 3, so (-3 abs(-15))/15 = ((3 (-1)) abs(-15))/(3×5) = 3/3×(-abs(-15))/5 = (-abs(-15))/5: (-1 abs(-15))/5
Since -15<=0, then abs(-15) = 15: (-15)/5
15/5 = (5×3)/5 = 3: Answer: |-3
