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Consider a random variable, X, with a normal distribution having mean 25 and standard deviation 79. What is P(-189.09 < X < 230.4)?

 Mar 6, 2015

Best Answer 

 #1
avatar+23254 
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z-score (lower)  =  (-189.09 - 25) / 79  =  -2.71

z-score (upper)  =  (230.4 - 25) / 79  =  2.6

normalcdf(-2.71, 2.6)  =  0.9919

 Mar 7, 2015
 #1
avatar+23254 
+5
Best Answer

z-score (lower)  =  (-189.09 - 25) / 79  =  -2.71

z-score (upper)  =  (230.4 - 25) / 79  =  2.6

normalcdf(-2.71, 2.6)  =  0.9919

geno3141 Mar 7, 2015

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