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what is p in the equation 

52p^2 + 84p + 18

Guest Oct 11, 2017
 #1
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Solve for p:
52 p^2 + 84 p + 18 = 0

 

Divide both sides by 52:
p^2 + (21 p)/13 + 9/26 = 0

 

Subtract 9/26 from both sides:
p^2 + (21 p)/13 = -9/26

 

Add 441/676 to both sides:
p^2 + (21 p)/13 + 441/676 = 207/676

 

Write the left hand side as a square:
(p + 21/26)^2 = 207/676

 

Take the square root of both sides:
p + 21/26 = (3 sqrt(23))/26 or p + 21/26 = -(3 sqrt(23))/26

Subtract 21/26 from both sides:


p = (3 sqrt(23))/26 - 21/26 or p + 21/26 = -(3 sqrt(23))/26

Subtract 21/26 from both sides:
p = (3 sqrt(23))/26 - 21/26       or        p = -21/26 - (3 sqrt(23))/26

Guest Oct 11, 2017

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