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what is (pi divided by six) minus 2 in fraction form? In terms of Pi?

 Sep 24, 2014

Best Answer 

 #1
avatar+5478 
+28

So your problem is:

$${\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\mathtt{2}}$$

 

You would need a common denominator to simplify this expression. Since pi is divided by 6, use 6 as the common denominator by multiplying 2 by (6/6):

 

 $${\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{6}}}}\right)$$

 

Simplified:

 

$${\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{12}}}{{\mathtt{6}}}}$$

 

Now you can combine the numerators:

 

$${\frac{\left({\mathtt{\pi}}{\mathtt{\,-\,}}{\mathtt{12}}\right)}{{\mathtt{6}}}}$$

 Sep 24, 2014
 #1
avatar+5478 
+28
Best Answer

So your problem is:

$${\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\mathtt{2}}$$

 

You would need a common denominator to simplify this expression. Since pi is divided by 6, use 6 as the common denominator by multiplying 2 by (6/6):

 

 $${\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{6}}}}\right)$$

 

Simplified:

 

$${\frac{{\mathtt{\pi}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{12}}}{{\mathtt{6}}}}$$

 

Now you can combine the numerators:

 

$${\frac{\left({\mathtt{\pi}}{\mathtt{\,-\,}}{\mathtt{12}}\right)}{{\mathtt{6}}}}$$

kitty<3 Sep 24, 2014

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