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What is tan60= 35/x simplified?

Guest Apr 6, 2017
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To solve for x:

\(\tan 60^{\circ}=\frac{35}{x} \\~\\ \frac{\sin60^{\circ}}{\cos60^{\circ}}=\frac{35}{x}\)

 

You can look at a unit circle to get exact values for sin60º and cos60º .

\(\frac{\frac{\sqrt3}{2}}{\frac12}=\frac{35}{x} \\~\\ \frac{\sqrt3}{2}*2=\frac{35}{x} \\~\\ \sqrt3=\frac{35}{x} \\~\\ x=\frac{35}{\sqrt3} \\~\\ x=\frac{35\sqrt3}{3}\)

hectictar  Apr 6, 2017

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