+9479 To solve for x:
\(\tan 60^{\circ}=\frac{35}{x} \\~\\ \frac{\sin60^{\circ}}{\cos60^{\circ}}=\frac{35}{x}\)
You can look at a unit circle to get exact values for sin60º and cos60º .
\(\frac{\frac{\sqrt3}{2}}{\frac12}=\frac{35}{x} \\~\\ \frac{\sqrt3}{2}*2=\frac{35}{x} \\~\\ \sqrt3=\frac{35}{x} \\~\\ x=\frac{35}{\sqrt3} \\~\\ x=\frac{35\sqrt3}{3}\)
