What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 5?

f(x) = −4 sin(2x + π) − 5

The function is in the form:

f(x) = A sin(Bx - C) + D

Where: |A| = amplitude2 π/B = period
C/B = phase shift

So the amplitude is:

|-4| = 4

The period is:

2 π/2 = π

And the phase shift is:

π / 2

As another note, the vertical shift is D, so for this function it would be -5, or 5 down.

I agree with all that kitty said except for the phase shift, which I think should be pi.

Umm I thought it should  be $$\pi/2$$  to the left.  i will have to do a graph  

http://web2.0calc.com/questions/graphing-trig-functions_1#r1

Actually, pi is the phase.  A phase shift  means the difference in phase from another sine wave.  Since no other wave is specified here, there isn't really a shift involved.  

Yes, pi/2 shown on my graph also Melody!  You (and kitty) are right that there is a pi/2 shift between these curves. 

You are also right Alan.

Since the original graph is not specified I am not sure that it is completely valid to talk about phase shift.