What is the answer for -16Tsquared+Tsquared+160 if T=0

No Dragon, you messed up.   :)

$$-16T^2+T^2+160 \qquad \mbox{when T=0}\\

=-16\times 0^2+0^2+160\\

=0+0+160\\

=160$$

$$\\\\\mbox{Write\;it\;down\;like\;this.}\\\\-16\0^2+0^2+160$$

Now, do the exponents.

$${\mathtt{\,-\,}}\left({{\mathtt{16}}}^{{\mathtt{2}}}\right) = -{\mathtt{256}}$$

$${{\mathtt{0}}}^{{\mathtt{2}}} = {\mathtt{0}}$$

Now add

$${\mathtt{\,-\,}}{\mathtt{256}}{\mathtt{\,\small\textbf+\,}}{\mathtt{160}} = -{\mathtt{96}}$$

So, $$-{\mathtt{96}}$$ Is your answer.

One simple mistake can ruin your future...

Relax, DS.....I doubt that  your mistake was enough to "alter" your future.....(but then again, you never know.......)

Sometimes, it does... Read the bible...