what is the answer to 4x^2-24x+32=0

$$\\4x^2-24x+32=0\\
$first simplify by dividing both sides by 4$\\
x^2-6x+8=0\\
$You need 2 numbers that mult to +8 and add to -6$\\
$ These numbers will be -4 and -2$\\
(x-4)(x-2)=0\\
x=4 \;or \;x=2$$

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$${\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{32}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{4}}\\
{\mathtt{x}} = {\mathtt{2}}\\
\end{array} \right\}$$

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